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university:courses:alm1k:circuits1:alm-cir-diode-rectifier [05 Jul 2020 20:07] – [Directions:] Doug Merceruniversity:courses:alm1k:circuits1:alm-cir-diode-rectifier [05 Jul 2020 20:17] – [Procedure:] Doug Mercer
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 The disadvantage of this circuit is that now two diode drops are in series with the load and the peak value of the rectified output is less than the AC input by 1.5 Volts rather than the 0.75 V in the previous circuits. The disadvantage of this circuit is that now two diode drops are in series with the load and the peak value of the rectified output is less than the AC input by 1.5 Volts rather than the 0.75 V in the previous circuits.
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 +**Added activities**
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 +Try replacing the diodes with RED (D<sub>1</sub>, D<sub>4</sub>) and GREEN (D<sub>2</sub>, D<sub>3</sub>) LEDs to match the arrows in figure 4. Reduce the AWG frequency to 10 Hz or less to see when the current is flowing in each diode.
  
 Connect a 100 uF capacitor across the bridge output to filter the rectified voltages. Be sure to note the correct polarity of the electrolytic capacitor with respect to the positive and negative outputs of the bridge. How does this filter cap change the voltage and current waveforms? Connect a 100 uF capacitor across the bridge output to filter the rectified voltages. Be sure to note the correct polarity of the electrolytic capacitor with respect to the positive and negative outputs of the bridge. How does this filter cap change the voltage and current waveforms?
university/courses/alm1k/circuits1/alm-cir-diode-rectifier.txt · Last modified: 03 Nov 2021 20:29 by Doug Mercer