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university:courses:alm1k:circuits1:alm-cir-diode-rectifier [05 Jul 2020 20:07] – [Directions:] Doug Mercer | university:courses:alm1k:circuits1:alm-cir-diode-rectifier [05 Jul 2020 20:17] – [Procedure:] Doug Mercer | ||
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The disadvantage of this circuit is that now two diode drops are in series with the load and the peak value of the rectified output is less than the AC input by 1.5 Volts rather than the 0.75 V in the previous circuits. | The disadvantage of this circuit is that now two diode drops are in series with the load and the peak value of the rectified output is less than the AC input by 1.5 Volts rather than the 0.75 V in the previous circuits. | ||
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+ | **Added activities** | ||
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+ | Try replacing the diodes with RED (D< | ||
Connect a 100 uF capacitor across the bridge output to filter the rectified voltages. Be sure to note the correct polarity of the electrolytic capacitor with respect to the positive and negative outputs of the bridge. How does this filter cap change the voltage and current waveforms? | Connect a 100 uF capacitor across the bridge output to filter the rectified voltages. Be sure to note the correct polarity of the electrolytic capacitor with respect to the positive and negative outputs of the bridge. How does this filter cap change the voltage and current waveforms? |