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resources:eval:user-guides:ad-fmcomms1-ebz:iq_correction [28 Aug 2013 22:54] – [Results] Di Puresources:eval:user-guides:ad-fmcomms1-ebz:iq_correction [29 Jun 2015 11:15] – [Math of I/Q Correction] Add missing negative sign for the tan() Lars-Peter Clausen
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 Then according to the linear algebra, <m>I(t)</m> and <m>Q(t)</m> can be obtained by doing a matrix inverse:  Then according to the linear algebra, <m>I(t)</m> and <m>Q(t)</m> can be obtained by doing a matrix inverse: 
  
-<m> [matrix{2}{1}{{I(t)} {Q(t)}}] =[matrix{2}{2}{alpha^{-1} 0 {alpha^{-1}tan(psi)} {sec(psi)}}] [matrix{2}{1}{{I prime prime(t)} {Q prime prime(t)}}] </m>.+<m> [matrix{2}{1}{{I(t)} {Q(t)}}] =[matrix{2}{2}{alpha^{-1} 0 {-alpha^{-1}tan(psi)} {sec(psi)}}] [matrix{2}{1}{{I prime prime(t)} {Q prime prime(t)}}] </m>.
  
 <WRAP info><m> [matrix{2}{1}{{I(t)} {Q(t)}}] =[matrix{2}{2}{A 0 C D}] [matrix{2}{1}{{I prime prime(t)} {Q prime prime(t)}}]=[matrix{2}{2}{A 0 C D}] [matrix{2}{1}{{I prime(t)-beta_I} {Q prime(t)-beta_Q}}] </m>,  <WRAP info><m> [matrix{2}{1}{{I(t)} {Q(t)}}] =[matrix{2}{2}{A 0 C D}] [matrix{2}{1}{{I prime prime(t)} {Q prime prime(t)}}]=[matrix{2}{2}{A 0 C D}] [matrix{2}{1}{{I prime(t)-beta_I} {Q prime(t)-beta_Q}}] </m>, 
resources/eval/user-guides/ad-fmcomms1-ebz/iq_correction.txt · Last modified: 21 Jan 2022 01:42 by Robin Getz